Question 206049
Solve
:
{{{7/((y^2-13y+36))}}} - {{{1/((y-9))}}} = {{{1/((3y-12))}}}
Factor
{{{7/((y-4)(y-9))}}} - {{{1/((y-9))}}} = {{{1/(3(y-4))}}}
Multiply by common denominator 3(y-4)(y-9), results:
3(7) - 3(y-4) = (y-9)
:
21 - 3y + 12 = y - 9
:
33 - 3y = y - 9
:
33 + 9 = y + 3y
:
42 = 4y
y = {{{42/4}}}
y = 10.5
:
:
Check solution:
{{{7/((10.5^2 - 13(10.5) + 36))}}} - {{{1/((10.5-9))}}} = {{{1/((3(10.5)-12))}}}
I'll let you check for equality here on a calc
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