Question 206275
Slope Intercept form is {{{y = mx + b}}}
Well first of all slope equals rise over run or...
{{{m = (y2-y1)/(x2-x1)}}} or {{{m = (DELTA*y)/(DELTA*x)}}} ({{{DELTA}}} is jsut a fancy way of saying change in or final minus initial)
And your two points are (2,-3) and (3,2)
which means that...
x1 =  2
x2 =  3
y1 = -3
y2 =  2
So just plug those values in and solve for m
- {{{m = (2-(-3))/(3-2)}}}
- {{{m = 5/1}}}
= {{{m = 5}}}
So your slope is a positive 5
Now that we have m, plug in m and one of your points into y = mx + b and solve for b
- {{{y = mx + b}}}
- {{{2 = (5)(3) + b}}}
- {{{2 = 15 + b}}}
- {{{2-15 = 15-15+b}}}
- {{{-13 = b}}}
So your equation in slope intercept form is {{{y = 5x - 13}}}