Question 206259
Remember that {{{log(a)-log(b)=log(a/b)}}}
So given {{{log3(3x+6)-log3(x-6)=2}}}
Simplify into {{{log3((3x+6)/(x-6))=2}}}
{{{2=log3(9)}}}
So, {{{log3((3x+6)/(x-6))=log3(9)}}}
Now you can remove the logarithms on both sides.
{{{((3x+6)/(x-6))=9}}}
{{{3x+6=9(x-6)}}}
{{{3x+6=9x-54}}}
{{{60=6x}}}
{{{x=10}}}