Question 206251
Yes you are doing it correctly but you messed up when you tried to solve the quadratic equation because...
- {{{17-y)^2 + y^2 = 169}}}
- {{{highlight(289) - 34y + y^2 + y^2 = 169}}}
- {{{17^2 = 289}}} , {{{17^2 <> 189}}}
So besides that you did it right but i'll go ahead and finish it for you
- {{{289 - 34y + 2y^2 = 169}}}
- {{{2y^2 - 34y + 289 - 169 = 169-169}}}
- {{{2y^2 - 34y + 120 = 0}}}
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*[invoke quadratic "x", 2, -34, 120]
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Since your solutions for x are 12 and 5, the side lengths are 12 and 5 because you get the same answer if x=12,y=5 as x=5,y=12
hope that helped!