Question 206246
1. Well...
- {{{(a-b)^2 = a^2 - 2ab - b^2}}} and likewise...
- {{{(a+b)^2 = a^2 + 2ab + b^2}}}
2. So simply plug in your equation
- {{{(2y-3)^2}}} 
- {{{a = 2y}}} and {{{b = 3}}}
- {{{(a-b)^2 = a^2 - 2ab - b^2}}} (The stuff on the left side isn't included in the formula i'm just leaving it over there for now to show you where i got the values from
- {{{(2y-3)^2 = (2y^2) - 2(2y)(3) - (3)^2}}}
3. Finally simplify
- {{{(2y^2) - 2(2y)(3) - (3)^2}}}
- {{{(2^2)(y^2) - 12y - 9}}}
= {{{4y^2 - 12y - 9}}} And there's your answer