Question 206134
N'(t) = {{{5t^2 - (0.04/(t^(2/3)))}}}

So the number of people who have heard about the product can be found by integrating N'(t).
integral({{{5t^2 - (0.04/(t^(2/3)))}}}) = {{{(5/3)t^3 - (0.12t^(1/3))}}}
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The first week encompasses days 0 to 7, so find {{{(5/3)t^3 - (0.12t^(1/3))}}}from 0 to 7.
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For the second week, find  {{{(5/3)t^3 - (0.12t^(1/3))}}} from 7 to 14.