Question 206114
1. First expand each term as much as possible
- {{{(18a^3*b^3)/(9a^3b)}}}
- {{{((3)(3)(2)a^3*b^3)/((3)(3)a^3b)}}}
- {{{(3*3*2*a*a*a*b^3)/(3*3*a*a*a*b)}}}
- {{{(3*3*2*a*a*a*b*b*b)/(3*3*a*a*a*b)}}}
2. Now cross out everything that's both on top and on bottom
- {{{(3*3*2*a*a*a*b*b*b)/(3*3*a*a*a*b)}}}
a. First 2 3's
- {{{(2*a*a*a*b*b*b)/(a*a*a*b)}}}
b. Next 3 a's
- {{{(2*b*b*b)/(b)}}}
c. Next 1 b
- {{{(2*b*b)/1}}}
3. Now simplify
- {{{(2*b*b)/1}}}
- {{{2b^2}}}
4. Your answer is {{{2b^2}}}