Question 28535
{54b4x4/16bx2}1/3
is actually (1/3){[54(b^4)(x^4)]/[16b(x^2)]
={(1/3)X54]/16}{b(b^3)(x^2)(x^2)/b(x^2)}
=[(2X3X3X3)/(3X2X8)]X [(b^3)(x^2)]
=[(3X3)/8][(b^3)(x^2)]
=(9b^3x^2)/8