Question 206029
{{{3/4}}} = 1 - {{{((3x-2))/((x+1))}}}
Multiply by 4(x+1)
4(x+1)*{{{3/4}}} = 4(x+1)*1 - 4(x+1)*{{{((3x-2))/((x+1))}}}
cancel the denominators, results:
3(x+1) = 4(x+1) - 4(3x-2)
:
multiply what's inside the brackets
3x + 3 = 4x + 4 - 12x + 8
:
Arrange the x's on the left
3x - 4x + 12x = 4 + 8 - 3
:
11x = 9
x = {{{9/11}}}