<PRE><B>Question 205939</B>
How much water must be added to 30 liters of a 75% salt solution to reduce it to 15%?
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Let x = amt of water required to this
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the amt salt remains the same, only the % salt changes
A simple equation
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.75(30) = .15(x + 30)
:
22.5 = .15x + 4.5
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22.5 - 4.5 = .15x
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18 = .15x
x = {{{18/.15}}}
x = 120 liters of water required
:
:
Check solution original equation (equal amt of salt)
.75(30) = .15(120 + 30)
22.5 = .15(150)
22.5 = 22.5
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Did this unconfuse you somewhat
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