Question 205965
What is the 2001st number in the sequence: 2, 5, 8, 11,...?
r = 3
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If 2 is the 1st:
n1 = 2
n2 = 5 (= 2 + 3*(n-1))
n3 = 8 (= 2 + 4*(n-1))
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.
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n2001 = 2 + (2001-1)*r
n2001 = 6002
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If 2 is the 0th, then it's 6005