Question 205915
Factor:
{{{N(t) = 3t^3+23t^2+8t}}}
{{{N(t) = t(3t^2+23t+8)}}} ...and that's the best we can do for the factoring part. To find {{{N(3)}}}, simply substitute {{{t = 3}}}
{{{N(3) = 3(3(3^2)+23(3)+8)}}}
{{{N(3) = 3(27+69+8)}}}
{{{N(3) = 3(104)}}}
{{{highlight(N(3) = 312)}}}