Question 205754
Assume the problem is:
{{{3/4}}} = 1 - {{{((3x-2))/((x+1))}}}
:
multiply the equation by 4(x+1)
4(x+1)*{{{3/4}}} = 4(x+1)*1 - 4(x+1)*{{{((3x-2))/((x+1))}}}
:
cancel out the denominators and you have:
3(x+1) = 4(x+1) - 4(3x-2)
:
3x + 3 = 4x + 4 - 12x + 8
:
combine like terms
3x + 3 = -8x + 12
:
3x + 8x = 12 - 3
:
11x = 9
x = {{{9/11}}}
;
:
Check the solution in the original equation, you can use the decimal .818 equiv
to get a close check on it
{{{3/4}}} = 1 - {{{((3(.818)-2))/((.818+1))}}}