Question 205740
Since
S(t) = t^3 + 2t^2
describes the distance
then the derivative is the speed:
S'(t) = 3t^2 + 4t
.
Now, we can plug it into:
E = mv^2/2
E = (2.4)(3t^2 + 4t)^2/2
You can expand the above...