<PRE><B>Question 205492</B>
The length of the Rhombus is 52cm. One of its diagonal is 48 cm. Find the length of the other diagonal and the area of the Rhombus.
:
you can see that the two diagonals form 4 identical right triangles
The hypotenuse = 52 cm (one side)
One leg = half the short diagonal which is 48cm = 24 cm
The other leg = half the longer diagonal (x)
:
Find the other leg (x)
x = {{{sqrt(52^2 - 24^2)}}}
x = 46.13
:
2 * 46.13 = 92.26 cm is the longer diagonal 
:
The area will be the total area of the 4 right triangles
:
2 * (46.13 * 24) = 2214.24 sq/cm; (area of the 4 triangles)
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