Question 205657
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The only two possibilities for a sum greater than 10 are 11 and 12.  There is one way to make a 12 and two ways to make an 11 out of 36 total possibilities.  So the probability of an 11 is: *[tex \Large \frac{2}{36}].  And the probability of a 12 is *[tex \Large \frac{1}{36}].  Finally, the probability of either an 11 or a 12 is the sum of these two probabilities:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{1}{36}\right)\ +\  \left(\frac{2}{36}\right)\ =\ \frac{3}{36}\ =\ \frac{1}{12}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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