Question 205482
The ratio of two sums of money is 4:3.
 If the larger sum of money is increased by 40$, the ratio becomes 2:1.
 Find the sum of the money.
:
Two sums of money:, x & y
"The ratio of two sums of money is 4:3."
{{{x/y}}} = {{{4/3}}}
Cross multiply
3x = 4y
x = {{{4/3}}}y
:
" If the larger sum of money is increased by 40$, the ratio becomes 2:1."
{{{((x+40))/y}}} = {{{2/1}}}
Cross multiply
2y = (x+40)
:
Find the sum of the money.
Replace x with {{{4/3}}}y in the above equation
2y = {{{4/3}}}y + 40
multiply equation by 3 to get rid of the denominator
3(2y) = 3*{{{4/3}}}y + 3(40)
6y = 4y + 120
6y - 4y = 120
2y = 120
y = $60 is the smaller amt
:
find x
x = {{{4/3}}}(60)
x = 4(20)
x = $80 is the larger amt