Question 205487
Let x, x+2, x+4 be the 3 odd numbers.
x/7+(x+2)/3+(x+4)/5=63
[(15x+35(x+2)+21(x+4)]/105=63
[15x+35x+70+21x+84]/105=63
[71x+154)/105=63
71x+154=63*105
71x+154=6,615
71x=6,615-154
71x=6,461
x=6,461/71
x=91 the first number
91+2=93 the second number
91+4=95 the third number
Proof:
91/7+93/3+95/5=63
13+31+19=63
63=63