Question 205385
3x^3 + 192
Factor out 3
3(x^3 + 64)
The sum of cubes can be factored to:
3(x + 4)(x^2 - 4x + 16)
:
:
2x^3 - 11x^2 + 12x + 9

Use long division or synthetic division (divide by 3):
(x-3)(2x^2 - 5x - 3)

Factor again
(x-3)(2x + 1)(x - 3)
:
;
9x^2 - 3x - 2
(3x - 2)(3x + 1)
:
:
and
2x^(5/4) + x^(3/4) - 15x^(1/4)
:
Factor out x^(1/4)
x^(1/4)[2x^(4/4) + x^(2/4) - 15]
:
which is
x^(1/4) [2x + x^(1/2) - 15]
:
Factors to
x^(1/4) [2x^(1/2) - 5][x^(1/2) + 3]