Question 28502
b)Solve by completing the square.
Show work in this space.
c)Solve by using the quadratic formula. 
Show work in this space. 
{{{x^2 - 3x + 2 = 0}}}
Solve by factoring:
(x-2) (x-1)
Set each equal to 0
x-2=0     x-1=0
Solve each equation
x=2        x=1

Solve by completing the square:
Subtract 2 from both sides to get the x's on one side of the equation, and any numbers on the other side.  
{{{x^2-3x=-2}}}
Take the middle term, divide by 2, and square it. 
{{{3/2=3/2}}}
{{{(3/2)^2=9/4}}}
Then add that number to both sides of the equation. Now you have:
{{{x^2-3x+9/4=-2+9/4}}}
{{{x^2-3x+9/4=1/4}}}
Now take x, the sign after {{{x^2}}} and the answer of the middle term divided by 2, put them in parenthesis and square it.
{{{(x-3/2)^2=1/4}}}
Now use the square root method to solve the problem. Square root both sides of the equation to get rid of the square. This gives you:
{{{x-3/2 = sqrt(1/4)}}}
Simplify. This gives you:
{{{x-3/2=+-1/2}}}
Now add {{{3/2}}} to both sides
{{{3/2+1/2}}}   {{{3/2-1/2}}}
x=2                 x=1