Question 205255
1st equation:
2x - y = 2
2x = 2 + y
divide it by 2:
x = 1 + y/2


2nd equation:
{{{y^2-4x=4}}}
{{{y^2-4(1+y/2)=4}}}
{{{y^2-4-2y=4}}}
{{{y^2-4-2y-4=0}}}
{{{y^2-2y-8=0}}}
factorize it:
(y - 4)(y + 2) = 0
y - 4 = 0 --> y = 4 --> x = 1 + 4/2 = 1 + 2 = 3
y + 2 = 0 --> y = -2 --> x = 1 + (-2)/2 = 1 - 1 = 0


so the solutions are: (3, 4) and (0, -2)