Question 28482
Solve:
{{{3x^2-2x = 15x-10}}} First get the equation into "standard" form. 
{{{3x^2-17x+10 = 0}}} Now factor the left side.
{{{(3x-2)(x-5) = 0}}} Apply the zero products principle.
{{{3x-2 = 0}}} and/or {{{x-5 = 0}}}
If {{{3x-2 = 0}}} then{{{3x = 2}}} and {{{x = 2/3}}}
If {{{x-5 = 0}}} then {{{x = 5}}}

The roots are:
{{{x = 2/3}}}
{{{x = 5}}}