Question 28483
Solve by completing the square:
{{{x^2+8x+13}}} Subtract 13 from both sides of the equation.
{{{x^2+8x = -13}}} Complete the square in the x-terms by adding the square of half the x-coefficient{{{(8/2)^2 = 16}}} to both sides.
{{{x^2+8x+16 = 3}}} Factor the left side.
{{{(x+4)^2 = 3}}} Take the square root of both sides.
{{{x+4}}}= +or-{{{sqrt(3)}}} Finally, subtract 4 from both sides.
{{{x = -4+sqrt(3)}}} or {{{x = -4-sqrt(3)}}}