<PRE><B>Question 204931</B>
Assume the problems is:
{{{x/3 + 5}}} = {{{5(x/5 - 4)}}}. Find the value of x.
;
{{{x/3 + 5}}} = {{{5x/5 - 5(4))}}}
Cancel 5
{{{x/3 + 5}}} = x - 20
Multiply by 3 to get rid of the denominator
x + 3(5) = 3(x - 20)
:
x + 15 = 3x - 60
:
15 + 60 = 3x - x
:
75 = 2x
:
x = {{{75/2}}}
x = 37.5
;
:
You can check solution in the original equation</PRE>