<PRE><B>Question 204911</B>
Find the equation of a straight line through (-3,2) that is perpendicular to X+3y=6 with the equation in standard form.
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The given line has slope = (-1/3)
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Any line perpendicular to it must have slope = 3
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Find the y-intercept:
2 = 3(-9)+b
2 = -27 + b
b = 29
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Equation: y = 3x + 29
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Cheers,
Stan H.</PRE>