Question 204828
where (h,k) is the vertex
the general equation is ___ y - k = a(x - h)^2


y - 4 = a(x - 5)^2


substituting to find a ___ 0 - 4 = a(1 - 5)^2 ___ -4 = 16a ___ -1/4 = a


so the equation is ___ y - 4 = (-1/4)(x - 5)^2