<PRE><B>Question 204807</B>
Two cards are drawn without replacement from an ordinary deck of 52 playing cards. What is the probability that both are spades if the first card drawn was a spade? 
I got so far that there are 13/52 and then you take away one giving you 12/52 and then I am lost.
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Yes, 13/52; but then 12/51.
Now multiply those fractions
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Using formulas you would get:
P(spade and then spade) = P(spade)*P(spade | spade) = (13/52)(12/51)= 0.0588..
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Cheers,
Stan H.</PRE>