Question 204780
because it can't be factorized, we can use this formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-4 +- sqrt( 4^2-4*1*(-2) ))/(2*1) }}}
{{{x = (-4 +- sqrt( 16+8 ))/2 }}}
{{{x = (-4 +- sqrt( 24 ))/2 }}}
{{{x = (-4 +- sqrt( 4*6 ))/2 }}}
{{{x = (-4 +- 2*sqrt( 6 ))/2 }}}
{{{x = -2 +- sqrt( 6 )}}}


so,
{{{x1 = -2 + sqrt( 6 )}}}
{{{x2 = -2 - sqrt( 6 )}}}