Question 204725
solve by using quadratic formula (((6x2+3x-18=0)))
my answer is x=-2 3/2
-b+- sq root of b^2-4ac/2a
a=6
b=3
c=18
so -3+-sqrt(9-4(6)l-18/12
-3t-sqrt9441)/12
-3+-21/12 and x=-3-21/12
x=-3+21/12 and x=-3-21/12
x=18/12=3/2 and x=-2
this is how I came up with this answer is this right?
{{{6x^2+3x-18=0}}}
{{{x^2 + 0.5x - 3 = 0}}}
*[invoke solve_quadratic_equation 1,.5,-3]
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Looks right.