Question 204676
Find the sum of the solutions to:
{{{x^2-12 = 4}}} Subtract 4 from both sides.
{{{x^2-16 = 0}}} Factor the left side.
{{{(x+4)(x-4) = 0}}} so the solutions are:
{{{x = -4}}} and {{{x = 4}}}
The sum of the solutions is:
{{{highlight(-4+4 = 0)}}}