Question 204627
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Let's divide: 

{{{3x^4+x^2+5}}} by {{{x-c}}} using synthetic division:

We must express {{{3x^4+x^2+5}}} as {{{3x^4+0x^3+x^2+0x+5}}}

 c | 3       0       1        0        5 
   |        3c      3c<sup>2</sup>     c+3c<sup>3</sup>   c<sup>2</sup>+3c<sup>4</sup>
    ----------------------------------------
     3      3c    1+3c<sup>2</sup>     c+3c<sup>3</sup>  5+c<sup>2</sup>+3c<sup>4</sup> 

The remainder is 5+c<sup>2</sup>+3c<sup>4</sup>.  This is always
a positive number because even powers of a
real number are never negative. Thus this
remainder can never be 0.

Edwin</pre>