Question 204615
Given:
{{{h = 51+20sin(225t)}}} Substitute t = 19
{{{h = 51+20sin(225(19))}}}
{{{h = 51+20sin(4275)}}}
{{{h = 51+20(-0.707)}}}
{{{h = 51+(-14.14)}}}
{{{h = 36.86}}} or...
{{{highlight(h = 36.9)}}}cm. (rounded to nearest tenth of a cm.)