Question 204614
Find the vertex of the parabola:
{{{y = 4x^2+8x+3}}}
The x-coordinate of the vertex is given by:
{{{x = (-b)/2a}}} and a = 4, b = 8, so...
{{{x = (-8)/2(4)}}}
{{{x = -1}}} now substitute this into the original equation and solve for y.
{{{y = 4(-1)^2+8(-1)+3}}}
{{{y = 4-8+3}}}
{{{y = -1}}}The vertex is at (-1, -1)
A parabola is the shape of the curve you get when you graph a quadratic equation.
{{{graph(400,400,-5,5,-5,5,4x^2+8x+3)}}}