<PRE><B>Question 204536</B>
1. Log base 8 X=1/3
x = 8^(1/3)
x = 2
.
2. Log e^x^2=125
x^2 = ln(125)
x^2 = 4.8283
x = 2.197
.
3. Solve for X: Log(5-2x)=log (3x+1)
5-2x = 3x+1
5 = 5x+1
4 = 5x
4/5 = x
0.8 = x
.
4. Solve for X: Log(x+1)-Log(x-1)=1
Log[(x+1)/(x-1)]=1
(x+1)/(x-1)= 10^1
(x+1)/(x-1)= 10
(x+1) = 10(x-1)
x+1 = 10x-10
1 = 9x-10
11 = 9x
11/9 = x
1.222 = x




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