Question 204352
Very  good,,,just  slightly  off
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Let  the  ?  be  the  expression  you  would  place in the  numerator to  fit.
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(-7yt)/(3x) = ? / (18xyt)
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lets  cross  multiply
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(3x) * ? = (-7yt)(18xyt)
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(3x)*? = -7*18 * x*y^2*t^2
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divide  thru  by  3x
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? = -42 y^2 t^2
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to  check
(-42y^2t^2) / (18xyt) = (-7 y t) / 3 x,,,,ok
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Have  a  good day