Question 204334
If {{{f(x) = x^2+1}}} and {{{g(x) = sqrt(x-1)}}} find {{{f(g(x))}}}
{{{f(g(x)) = f(sqrt(x-1))}}} and...
{{{f(sqrt(x-1)) = (sqrt(x-1))^2+1}}}={{{(x-1)+1 = x}}}