<PRE><B>Question 204297</B>
The bank officer rates applicants for credit. Ratings are normally distributed. The mean is 240 and the standard deviation is 60. If 36 applicants are randomly chosen, what is the probability that they will have a rating between 230 and 260? 
-------------------------
Find the z-value of 230 and of 260:
z(230) = (230-240)/(60/sqrt(36)] = 60/60 = 1
---
z(260) = (260-240)/(60/sqrt(36)) = 20/[60/6) = 2
--------------------------------
P(230 &lt; x &lt; 260) = P(1 &lt; z &lt; 2) =  0.1359...
---------------------------------
Cheers,
Stan H.</PRE>