Question 28352
{{{4y^2}}}+9y-28=0
First of all look at the second sign in the equation; it is -, so that means when you factor, one sign is - and the other is +. Now the first sign is +, so that means the larger number is going to be +.
So begin by listing all your factors of 4, and factors of 29,
when you do you need to decide which ones, when subtracted together the = 9;
you should have found that they are; 4*1, and 4*7;
(4y+7)(y+4)
Hope you understand
=)