Question 203964
Volume  of  sphere  =  (4/3) pi *r^3
.
Delta  V = (4/3) pi *{ (alpha) (*r)*(delta T) }^3
.
alpha  for  alum  = 24 * 10^-6,
Radius  = .4 m
delta T = (45-2)=43 deg  C
.
Delta  V = (4/3) pi * { (24*10-6) * .4 * 43)}^3 = 2.946 *10^-10
.
.
Volume  of  Cylinder = B*h = (pi * r^2) * h
.
Delta  V = pi { (alpha)(r)(delta T)}^2 * { (alpha)(h)( delta T)}
.
alpha  copper = 17 *10^-6
r=.2
h=3
delta T = (35-14) = 21
.
delta  V = pi *{(17*10^-6)(.2)(21)}^2 * {(17*10^-6)(3)(21)}
.
delta  V = 1.7153 *10^-11
.
Therefore the  alum  sphere  has  greater  volume  change
.
approx  3*10^-10 vs 2*10^-11