Question 28390
Eqation:
{{{75/(x+5)-75/x)=0.5}}}
75[(x+5)-(x)=0.5[(x)(x+5)]
{{{75(5)=0.5(x^2+5x)}}}
{{{375=0.5x^2+2.5x}}}
{{{0.5x^2+2.5x-375=0}}}


Use quadratic formula:
a= 0.5 b = 2.5, c = -375
{{{x=(-2.5+-sqrt(2.5^2-4*0.5*-375))/(2*0.5)}}}
Simplfy x = -30 and x= 25
Remvoe the negative x = 25


Hence, about 25 people attendented the party.
Paul.