Question 203983
You're given the "a" to use. You only need to figure out the relationship between  "k" and "p". The relationship is:
{{{k = p/(2pi)}}}
Substituting your "p" (period) into this we get:
{{{k = ((3pi)/2)/(2pi) = ((3pi)/2)* (1/(2pi)) = 3/4}}}
So your equation is:
{{{y = (1/2)sin((3/4)x)}}}