Question 203973
To factor, use "grouping" technique:
x^7-x^6-64x+64
= (x^7-x^6)-(64x-64)
= x^6(x-1)-64(x-1)
= (x^6-64)(x-1)
But wait, we still factor left term:
= (x^3-8)(x^3+8)(x-1)