Question 203968
solve this quadratic equation for x: 3x^2 + 4x - 8 = 0.
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Use the quadratic formula to get:
x = [-4 +- sqrt(16 - 4*3*-8)]/6
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x = [-4 +- sqrt(112)]/6
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x = [-4 +- 4sqrt(7)]/6
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x = (-2/3) +- (2/3)sqrt(7)
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Cheers,
Stan H.