Question 203858
What is the square root of 24m21n51?
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Assuming the 21 and 51 are exponents:
{{{sqrt(24m^21*n^51)}}}
= {{{sqrt(24)*sqrt(m^21)*sqrt(n^51)}}}
Separate the exponents to get the largest even numbers.
= {{{sqrt(4)*sqrt(6)*sqrt(m^20)*sqrt(m)*sqrt(n^50)*sqrt(n)}}}
= {{{2sqrt(6)*m^10*sqrt(m)*n^25*sqrt(n)}}}
= {{{2m^10n^25*sqrt(6mn)}}}