Question 203863
Give points which are outside and pont which are inside of the circles in this equation: x^2+y^2+6x=0
------------------
You need to find the center and the radius of the circle.
Put it into standard form,
(x-h)^2 + (y-k)^2 = r^2 where the center is at (h,k) and the radius is r.
x^2+y^2+6x=0
Complete the square for the x terms.
x^2 + 6x + 9 + y^2 = 9
(x+3)^2 + y^2 = 3^2
So the center is (-3,0) and the radius is 3.
----------------------------
Assuming you mean all points inside and out:
Inside:
(x+3)^2 + y^2 <9
Outside:
(x+3)^2 + y^2 >9
------------------
That's it.  This one could have been shortcutted, but that might not apply in all cases.  Changing the = to < and > might move the center of the circle.