Question 203815
q^2 -3q +18 =0
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if  it  was  q^2 -3q-18=(q-6)(q+3)
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however  as  it  stands  use  quadratic  formula
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a=1,,,b=-3,,,c=18
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q= [ -(-3) +/- sqrt{ (-3)^2 -4(1)(18) ] / 2(1)
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q= [3 +/- sqrt{9-72} ] /2
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q=[ 3+/- (7.94 i ) /2
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q= 3/2 +/- 3.97 i