Question 203698
(x^2 -25)/x  / (x+5)/(x^2-5x)
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invert  and  multiply,  as  with  fractions ,,,a/b  / c/d = (a/b) * (d/c)
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(x^2 -25)/x  * (x^2-5x) / (x+5)
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factor and  combine  like  terms
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{ (x+5)(x-5)} /x * { (x)(x-5) } / (x+5)
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(x-5)* (x-5)
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(x-5)^2
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check,,,let  x=1,,,both  original  and  answer = 16,,,ok