Question 203602
Having trouble figuring out how to due this can someone help please... 
Use integration by substitution to find.. 
int(3x^2-2)(x^3-2x)^7 dx 
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Let u = x^3-2x
Then du = 3x^2-2 dx
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Substitute into your original integral and you get:
int[u^7 du]
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Integrate wrt u to get:
(1/8)u^8 + C
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Substitute back into "x" to get:
= (1/8)(x^3-2x)^8 + C
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Cheers,
Stan H.