Question 203550
n(.05) + d(.10) = 6.05 ___ 5n + 10d = 605 ___ 5n = 605 - 10d


(n - 10)(.05) + 2d(.10) = 9.85 ___ 5n - 50 + 20d = 985


substituting ___ 605 - 10d - 50 + 20d = 985 ___ 10d = 430 ___ d = 43


substituting ___ 5n = 605 - 430 ___ 5n = 175 ___ n = 35