Question 203491
Start with te formula for the volume of a cone:
{{{V[c] = (1/3)(pi)r^2*h}}} Substitute: r = 6ft., h = 10ft. and {{{pi = 3.14}}} approx.
{{{V[c] = (1/3)(3.14)(6^2)(10)}}}
{{{V[c] = 376.8}}}cu.ft.
Since 1 cu.ft = 7.480510 gallons of water, then the capacity, C, is...
{{{C = (376.8)*(7.480510)}}}
{{{C = 2818.656}}}Gallons. Rounded to the nearest hundredth, this is:
{{{highlight(C = 2818.66)}}}Gallons.